9-8x^2=(-503)

Solution for 9-8x^2=(-503) equation:

9-8x^2=(-503)

We move all terms to the left:

9-8x^2-((-503))=0

We add all the numbers together, and all the variables

-8x^2+512=0

a = -8; b = 0; c = +512;
Δ = b2-4ac
Δ = 02-4·(-8)·512
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-128}{2*-8}=\frac{-128}{-16}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+128}{2*-8}=\frac{128}{-16}
=-8
$